BITSAT Sample Paper 2008. Question Papers
Q3. Two circles x2 + y2 – 6x + 8 = 0 and x2 + y2 – 6 = 0 are given. The equation of the circle through their point of intersection and the point (1,1) is
a) x2 + y2 -3x + 1 b) x2 + y2 – x + 5 = 0
c) x2 + y2 -8x + 6y = 8 d) x2 + y2 – 4x + 8y = 7
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