Education and Career Forum

i have got 51.33 marks and my rank is 1374 in computer science branch in gate 2011 can any one tell me that which iit i can get and to which i should apply..

i want to know number of total seats of iit in punjab

what is the rank needed to get admission into iit madras

i have wiritten my gate 2011 in IN stream. my gate score is 358 and my rank 1836 have applied in iit-m i come under sc category.they have already released 3 offer letters and i have nt yet been offered a seat so are there any possibilities of me getting a seat.

Originally Posted by tridibkumarbose

i am a computer science student in 2nd year .i want to apper for the GATE2011.then in the year 2012 i want repeat the exam. is it a right decision?
will I get any benifit on my decision?
how many seat are there in the IITs for the M.Tech in Computer Science?

There are 7 IITs in India.
Let me assume that its IIT chennai.
60seats are available in IIT for M.TECH Computer Science

Hi dear,

Certain number of seats are reserved for candidates belonging to SC/ST/OBC
categories and Person with Disabilities (PD) as per the Govt. of India rules. For
details refer to the Information Brochure.

Thanks

Originally Posted by tridibkumarbose

i am a computer science student in 2nd year .i want to apper for the GATE2011.then in the year 2012 i want repeat the exam. is it a right decision?
will I get any benifit on my decision?
how many seat are there in the IITs for the M.Tech in Computer Science?

In iits for computer science students approx 300 seats are their but specifically speaking of the colleges go through information brochure...first give exam and as gate score is valid for 2 years by same marks you can apply and if you didn't score well than appear again best between 2 is selected ...
regards,
sharad

TOP IIT COLLEGE FOR M.TECH CSE

Presently i m doing job in it sector as fresher.I got admission in nbrc manesar for integrated phd programme.Should i laeve my job and opt for phd.if yes tel me career option after getting phd degree from nbrc?